Progression Quiz | Aptitude Important MCQ
Quiz solution given below the Post
- (A) 1922
- (B) 1891
- (C) 1829
- (D) 1860
- (A) Does not exist
- (B) 1
- (C) 0
- (D) -1
- (A) 56
- (B) 28
- (C) 21
- (D) 42
- (A) 5643
- (B) 5640
- (C) 2928
- (D) 5673
5 >>Q7. The sum of infinity of the terms of a G.P. is 120. The sum to infinity of the squares of the terms of the same G.P. is 2880. What will be the series? ?
- (A) 20, 20/7, 180/14, ....
- (B) 40, 80/3, 160/9, ...
- (C) 8, 16/3, 32/9, ...
- (D) None of these
- (A) 4
- (B) 6
- (C) 12
- (D) 3
- (A) 18
- (B) 16
- (C) 14
- (D) 12
- (A) 23/50
- (B) 23
- (C) 50
- (D) 50/23
- (A) 883
- (B) 887
- (C) 885
- (D) 889
10 >>Q18. The first term of an P. consisting of 30 terms is 10 and the common difference is 5. What will be the ratio of the sum of 30 terms of the progression and the sum of the last 20 terms of the progression? ?
- (A) 99:89
- (B) 99:83
- (C) 99:80
- (D) 99:86
- (A) Rs.10.5
- (B) Rs.l4
- (C) Rs.8
- (D) Cannot be determined
- (A) 32
- (B) 18
- (C) 21
- (D) 24
- (A) 35
- (B) 20
- (C) 24
- (D) 30
- (A) 12th
- (B) 8th
- (C) 10th
- (D) 11th
- (A) 864 cm²
- (B) 512 cm²
- (C) 1024 cm²
- (D) None of these
16 >>Q26. The sum of first four terms of a G.P. is 120. The sum of its first two terms is 12. What will be the first term, if all its terms are (+ ve) ? ?
- (A) 5
- (B) 4
- (C) 3
- (D) 2
- (A)
- (B)
- (C)
- (D)
- (A)
- (B)
- (C)
- (D)
- (A)
- (B)
- (C)
- (D)
- (A)
- (B)
- (C)
- (D)
1 >>Q1. How many numbers are there in between 55 and 4505 which are multiples of 5 and divisible by 3? ?
- (A) 297
- (B) 296
- (C) 287
- (D) 295
- (A) n² :n+2
- (B) n:n+3
- (C) n:2(n+2)
- (D) n:2(n+3)
- (A) 1922
- (B) 1891
- (C) 1829
- (D) 1860
- (A) Does not exist
- (B) 1
- (C) 0
- (D) -1
5 >>Q5. The sum of first twenty terms of an arithmetic progression is 210. What will be the sum of its 10th and 11th term? ?
- (A) 56
- (B) 28
- (C) 21
- (D) 42
- (A) 5643
- (B) 5640
- (C) 2928
- (D) 5673
- (A) 20, 20/7, 180/14, ....
- (B) 40, 80/3, 160/9, ...
- (C) 8, 16/3, 32/9, ...
- (D) None of these
- (A) 16,8,4
- (B) 2,8,4
- (C) 4, 8, 20
- (D) 10, 16, 21
- (A) 4
- (B) 6
- (C) 12
- (D) 3
10 >>Q10. The sum of three numbers in an P. is 36. The sum of their squares is 440. What will be the largest among the three numbers? ?
- (A) 18
- (B) 16
- (C) 14
- (D) 12
- (A) 23/50
- (B) 23
- (C) 50
- (D) 50/23
- (A) 8, 12, 14
- (B) 10, 12, 14
- (C) 12, 16, 16
- (D) 20, 22, 26
Download Progression MCQ Aptitude
13 >>Q13. A total of 255 coins is placed in n boxes, such that a person can take any number of coins from 1 to 255 by selecting a suitable combination of one or more than 1 boxes out of n boxes, the minimum value of n is ________________. ?- (A) 5
- (B) 6
- (C) 7
- (D) 8
- (A) 34
- (B) 38
- (C) 35
- (D) 36
- (A) 5
- (B) -5
- (C) -4
- (D) 4
- (A) 883
- (B) 887
- (C) 885
- (D) 889
- (A) -3 if n is odd
- (B) 0 if n is even
- (C) Both and
- (D) None of these
- (A) 99:89
- (B) 99:83
- (C) 99:80
- (D) 99:86
- (A) Rs.10.5
- (B) Rs.l4
- (C) Rs.8
- (D) Cannot be determined
- (A) 32
- (B) 18
- (C) 21
- (D) 24
Solution of Progression Quiz
1 | |
2 | Exp. Sum of 3rd term and 60th term= a+2d + a+59d = 60,2a + 61d = 60.Sum of 62 terms= (62/2)(2a + (62-1)d)= 31(2a+61d)= 31(60) = 1860. |
3 | Exp. Sum to infinity exists only for a descending GP. |
4 | Exp. Sum of first twenty terms of an P.= (20/2)(2a + (20-1)d)= 210, 2a + 19d21Sum of 10th and 11th term = a+9d + a+10d = 2a + 19d = 21. |
5 | Exp. Sum of AP = (n/2)(2a + (n-1)d).a = 3, d = 6 - 3 = 3.a + (n-1)d = 183, n = 61.Sum = (61/2)(2x3 + (60)3) = (61/2)(186) = 5673. |
6 | Exp. Let 'a' be the first term and 'r' be the common ratio.Sum to infinity of GP = a/(1-r) = 120.Sum to infinity of squares of the terms of GP = a^2 / (1 - r^2) = 2880.a/(1-r) x a/(1+r) = 2880.120 x a/(1+r) = 2880.a/(1+r) = 24.a = 40, r = 2/3. |
7 | |
8 | Exp. Only three such three digit numbers exist, 124, 139, 248. |
9 | Exp. Let the three numbers be a-d, a , a+d.a-d + a + a+d = 36, a = 12.(a-d)² + a² + (a+d)² = 440.3a² + 2d² = 440.3(12²) + 2d² = 440, 2d² = 440 - 3(144).2d² = 8, d = 2.Largest number = a+d = 12+2 = 14. |
10 | Exp. Last term of AP = a + (n-1)d = 55.Sum of AP = (n/2)(a + a + (n-1)d) = 720.(n/2)(5 + 55) = 720.n = 24.a + (n-1)d = 55, 5 + 23d = 55, d = 50/23. |
11 | |
12 | |
13 | Exp. a + 4d = 23.a + 9d = 48, a + 4d + 5d = 48, 23 + 5d = 48, d = 5.a + 4x5 = 23, a = 3.8th term = a + 7d = 3 + 7x5 = 38. |
14 | |
15 | Exp. Difference of 9th and 8th terms of a GP= a x r&sup8; - a x r&sup7;= a x r&sup7; x (r - 1)896Similarly, difference between 2nd and 1st term= a(r-1) = 7.From the two equations, r&sup7;= 896/7 = 128, r = 2.Hence, we have a = 7.Sum of first 7 terms of GP= a(r&sup7; - 1)/(r-1)= 7(128-1)/(2-1) = 896. |
16 | |
17 | Exp. Sum of 30 terms = (30/2)(2x10 + 29x5) = 2475.Sum of first 10 terms = (10/2)(2x10 + 9x5) = 325.Sum of last 20 terms = 2475 - 325 = 2150Ratio = 2475/2150 = 99/86. |
18 | Exp. Let amount saved by Ankit in first month =Let amount saved by Ashok in first month =Sum saved by Ankit after 20 months= (20/2)(2A + 19B).Sum saved by Ashok after 20 months= (20/2)(B + 19A).Total sum= 10(A + 19B) + 10(B + 19A)= 200A + 200B = 2100.A + B = 10.5.Total amount saved by Ankit in second months= A + (2-1)B = A + B = 10.5. |
19 | Exp. a = 16.16³ = 7 x (16³/(1-r³) - 16³).r = 0.5.Sum to infinity = a/(1-r) = 16/(1-0.5) = 32. |
20 |