Time & Work Quiz | Aptitude Important MCQ with Solution #mcq_CetJob

Time & Work Quiz | Aptitude Important MCQ 

1 >>Q1. Deepa and Poonam can do a piece of work in 8 days. Deepa alone can do the work in 10 days. In how many days, can Poonam finish the work alone? ?

• (A) 40 days
• (B) 45 days
• (C) 50 days
• (D) 35 days

Solution Exp. Amount of work done by Deepa in 8 days 0.8Amount of work done by Poonam in 8 daysTRUETime taken by Poonam to complete the work alone= 8x5= 40 days(to complete 2/10 x 5 = 1 work).

2 >>Q2. A is twice as fast as B and C together. If B and C can do the work in 10 and 30 days respectively, in how much time can A finish the work alone? ?

• (A) 3.33 days
• (B) 3.75 days
• (C) 3.66 days
• (D) 3.25 days

Solution Exp. Number of days taken by B and C to complete the work together= 1/(1/10 + 1/30) = 7.5 days.A takes 7.5/2 = 3.75 days.

3 >>Q9. 8 cats can eat 8 mice in 8 minutes. How many cats can eat 6 mice in 16 minutes? ?

• (A) 8
• (B) 6
• (C) 3
• (D) 4

Solution Exp. Let number of cats =(8 cats)x(8 minutes) / 8 mice= A x (16 minutes) / 6 mice.A = 3.

4 >>Q10. P can do a work in 24 days and Q can do the work in 21 days. P starts the work and works for 9 days, then Q also joins P. In how many days in all, will the work be completed? ?

• (A) 17
• (B) 15
• (C) 16
• (D) 18

Solution Exp. Amount of work completed by P in 9 daysTRUEWork to be completedTRUENumber of days required by P and Q to complete rest of the workTRUETotal number of days = 9 + 7 = 16.

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5 >>Q11. P and Q can do a piece of work in 15 days, Q and R can do the work in 20 days. P and R can do the work in 12 days. In how many days can P finish the work? ?

• (A) 18
• (B) 20
• (C) 17
• (D) 22

Solution Exp. Let time taken by P, Q and R alone to complete the work = A, B andWe have, (1/A + 1/B)0.06666666666666671/B + 1/C0.051/A + 1/C0.0833333333333333Solving the three equations, A = 20.

6 >>Q12. 12 rabbits can eat 12 carrots in 12 minutes. In how many minutes can 4 rabbits eat 4 carrots? ?

• (A) 10
• (B) 12
• (C) 8
• (D) 4

Solution Exp. Let A be the number of minutes required.(12 rabbits) x (12 minutes) / 12 carrots = (4 rabbits) x A / 4 carrots.A = 12.

7 >>Q13. 5 men can do a piece of work in 10 days and 6 women can do the same work in 15 days. In how many days can 2 men and 3 women together do the work? ?

• (A) 12.818
• (B) 13.182
• (C) 13.637
• (D) 12.454

Solution Exp. Amount of work completed by one man in one day0.020.02Amount of work completed by one woman in one day0.01111111111111110.0111111111111111Amount of work done by 2 men and 3 women in one day0.07333333333333330.0733333333333333Number of days required to complete the job13.636363636363613.6363636363636= 13.637.

8 >>Q14. P is 60% more efficient than Q. If P alone can do the work in 20 days, in how many days, can Q finish the work alone? ?

• (A) 32
• (B) 22.5
• (C) 28
• (D) 12.5

Solution Exp. Let Q finish the work in A number of days.Since P is 60% more efficient than Q, 1.6/A = 1/20.A = 32.

9 >>Q15. One man can load 3 boxes in 12 minutes. How many trucks can 12 men load completely in 1 hour given that each truck can hold 8 boxes? ?

• (A) 24
• (B) 21
• (C) 23
• (D) 22

Solution Exp. Let A be the number of boxes 12men can load in 1hour (60 minutes).(1man)x(12minutes) / 3 boxes = (12men)x(60minutes) /A = 180, i.e. Number of trucks loaded = 180/8 = 22.5.Number of trucks loaded fully = 22.

10 >>Q16. C takes 2 times as long as A and B together take to complete a piece of work. Working together A, B and C can complete the work in 15 days. In what time can C alone do the work? ?

• (A) 40 days
• (B) 54 days
• (C) 50 days
• (D) 45 days

Solution Exp. Let A, B and C take X, Y and Z days to finish the work alone.Amount of work completed by C in a day = 1/Z.Amount of work completed by A and B together in a day = 1/X + 1/Y.We have, 2(1/Z) = (1/X + 1/Y)Number of days taken by A, B and C to finish the work together= 15days.1/(2/Z + 1/Z) = 15,Z = 45days.

11 >>Q17. A sum of money is sufficient to pay A's wage for 16 days or B's wage for 12 days. For how many days is the sum sufficient to pay the wages for both A and B? ?

• (A) 5.71428571428571
• (B) 6.71428571428571
• (C) 5.85714285714286
• (D) 6.85714285714286

Solution Exp. Number of days the sum will be sufficient topay the wages for both A and B6.857142857142866.85714285714286= 6 6/7.

12 >>Q18. A and B can complete a piece of work in 12 and 15 days respectively. They began to work together, but A left the work after 4 days due to illness. In how many days B alone will finish the remaining work? ?

• (A) 6 days
• (B) 7 days
• (C) 8 days
• (D) 9 days

Solution Exp. Amount of work completed in 4 days = 4/12 + 4/15 = 3/5.To complete the remaining 2/5th of the work, B requires (2/5) x 15 = 6 days.

13 >>Q19. A, B and C can do a piece of work in 48, 36 and 12 days respectively. A started the work, after m days B joins him and after m more days C joins them and the work is completed in 12 days. What is the value of m? ?

• (A) 5
• (B) 4
• (C) 3
• (D) 2

Solution Exp. Work done by A in m days = m/48.Work done by A and B in next m days = m/48 + m/36.Work done by A, B and C in remaining days = (12-2m)/48 + (12-2m)/36 + (12-2m)/12.m/48 + m/48 + m/36 + (12-2m)/48 + (12-2m)/36 + (12-2m)/12 = 1.m = 3.

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14 >>Q21. A hostel of 630 men has provisions for 24 days when consumption is 2 kg per day per man. For how many days are the provisions sufficient for 360 men at the rate of 3 kg per day per two men? ?

• (A) 56
• (B) 44
• (C) 52
• (D) 48

Solution Exp. Amount of provisions = 630 x 24 x 2 = 30240.Let A be number of days the provisions last in second case.360 x A x 3/2 = 30240.A = 56.

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15 >>Q22. 1 man can load 1 box in a truck in 8 minutes and the truck can hold 6 boxes. How many truck are completely loaded by 16 men in 1 hour 10 minutes? ?

• (A) 25
• (B) 24
• (C) 22
• (D) 23

Solution Exp. Let number of boxes loaded be(1man)x(8minutes) / (1box)= (16men)x(70minutes) / (A).A = 140.Number of trucks filled = 140/6 = 23.33.Number of trucks completely filled = 23.

16 >>Q23. A well is 30 feet deep. A frog jumps 3 feet in one minute and comes down by 1 foot in the next minute. In what time does the frog get out of the well? ?

• (A) 28.66 min
• (B) 29.33 min
• (C) 30.00 min
• (D) None of these

Solution Exp. The relative distance covered in two minutes = 2 feet.The frog covers 28 feet in 28 minutes.To cover the next two feet, it takes 2/3 minutes.Total time taken = 28 2/3 = 28.66 minutes.

17 >>Q24. A sum of money is sufficient to pay A's wage for 20 days or B's wage for 30 days. For how many days, is the sum sufficient to pay the wages for both A and B? ?

• (A) 13
• (B) 14
• (C) 12
• (D) 15

Solution Exp. Number of days1212

18 >>Q25. One man, one woman and one child can do a piece of work in 10 days. One man can do the work in 30 days and one woman can do it in 20 days. In how many days can one child do the work? ?

• (A) 60
• (B) 55
• (C) 65
• (D) 50

Solution Exp. Let the child take A days to complete the work alone.We have, 1/30 + 1/20 + 1/A = 1/10.A = 60.

19 >>Q27. In a fort, there was food-material for 1200 soldiers for 60 days. If after 15 days, 200 soldiers go away, then for how many days will the remaining food-material be sufficient to be remainders ? ?

• (A) 45 days
• (B) 54 days
• (C) 59 days
• (D) 49 days

Solution Exp. After 15 days, the food material remaining can last for 45 days if 1200 soldiers are in the fort.If one soldier is in the fort, it will last for 45 x 1200 days.If 1000 soldiers (1200 - 200) are in the fort, the fod will last for 45 x 1200 / 1000 = 54days.

20 >>Q28. In a barrack, there is food for 110 soldiers for 40 days. After 10 days 40 soldiers come. For how many days will the food be sufficient? ?

• (A) 22
• (B) 21
• (C) 20
• (D) 19

Solution Exp. After 10 days, food left is sufficient to feed 110 soldiers for 30 days.It would be sufficient to feed one soldier for 30 x 110 days.Hence, it would be sufficient to feed 150 soldiers (110 + 40) for 30 x 110 / 150 = 22days.

Solved Examples from RS Agrawal

1	Exp. Amount of work done by Deepa in 8 days  0.8Amount of work done by Poonam in 8 daysTRUETime taken by Poonam to complete the work alone= 8x5= 40 days(to complete 2/10 x 5 = 1 work).
2	Exp. Number of days taken by B and C to complete the work together= 1/(1/10 + 1/30) = 7.5 days.A takes 7.5/2 = 3.75 days.
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7	Exp. Let A be the number of units produced by 6 men in 6 days.(2men)x(2days) / 2000= (6men)x(6days) /A = 18000.
8	Exp. Work completed by P in 5 days TRUEWork completed by P and Q in 7 days (5 + 2)TRUEWork to be completed = 1 - 43/1000.57Amount of days required33Total number of daysTRUE
9	Exp. Let number of cats =(8 cats)x(8 minutes) / 8 mice= A x (16 minutes) / 6 mice.A = 3.
10	Exp. Amount of work completed by P in 9 days TRUEWork to be completedTRUENumber of days required by P and Q to complete rest of the workTRUETotal number of days = 9 + 7 = 16.
11	Exp. Let time taken by P, Q and R alone to complete the work = A, B andWe have, (1/A + 1/B)0.06666666666666671/B + 1/C0.051/A + 1/C0.0833333333333333Solving the three equations, A = 20.
12	Exp. Let A be the number of minutes required.(12 rabbits) x (12 minutes) / 12 carrots = (4 rabbits) x A / 4 carrots.A = 12.
13	Exp. Amount of work completed by one man in one day0.020.02Amount of work completed by one woman in one day0.01 Amount of work done by 2 men and 3 women in one day0.073 Number of days required to complete the job13.63= 13.637.
14	Exp. Let Q finish the work in A number of days.Since P is 60% more efficient than Q, 1.6/A = 1/20.A = 32.
15	Exp. Let A be the number of boxes 12men can load in 1hour (60 minutes).(1man)x(12minutes) / 3 boxes = (12men)x(60minutes) /A = 180, i.e. Number of trucks loaded = 180/8 = 22.5.Number of trucks loaded fully = 22.
16	Exp. Let A, B and C take X, Y and Z days to finish the work alone.Amount of work completed by C in a day = 1/Z.Amount of work completed by A and B together in a day = 1/X + 1/Y.We have, 2(1/Z) = (1/X + 1/Y)Number of days taken by A, B and C to finish the work together= 15days.1/(2/Z + 1/Z) = 15,Z = 45days.
17	Exp. Number of days the sum will be sufficient topay the wages for both A and B6.857142857142866.85714285714286= 6 6/7.
18	Exp. Amount of work completed in 4 days = 4/12 + 4/15 = 3/5.To complete the remaining 2/5th of the work, B requires (2/5) x 15 = 6 days.
19	Exp. Work done by A in m days = m/48.Work done by A and B in next m days = m/48 + m/36.Work done by A, B and C in remaining days = (12-2m)/48 + (12-2m)/36 + (12-2m)/12.m/48 + m/48 + m/36 + (12-2m)/48 + (12-2m)/36 + (12-2m)/12 = 1.m = 3.
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